A,B,C are interior angle of triangle ABC prove that cosec A+B/2 is equ

1.	A,B,C are interior angle of triangle ABC prove that cosec A+B/2 is equal to sec c/2
Answer» LHS=Cosec[(A+B)/2】=cosec[(180-C)/2]=Cosec[90-C/2]=Sec C/2=RHS

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