1.

A bag contains 3 black, 7 brown, 4 green marbles. What is the probability of getting a green ball?(a) \(\frac {1}{9}\)(b) \(\frac {7}{9}\)(c) \(\frac {2}{7}\)(d) \(\frac {4}{9}\)The question was asked at a job interview.My enquiry is from Theoretical Approach to Probability topic in chapter Probability of Mathematics – Class 10

Answer»

Right answer is (c) \(\frac {2}{7}\)

Easy EXPLANATION: Total NUMBER of OUTCOMES = 3 + 7 + 4 = 14

Favorable outcomes of getting a green ball = 4

P(E) = \(\frac {Number \, of \, favorable \, outcomes}{Total \, number \, of \, outcomes} = \frac {4}{14}\)

= \(\frac {2}{7}\)



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