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A body is moving with uniform velocity of `8 ms^-1`. When the body just crossed another body, the second one starts and moves with uniform acceleration of `4 ms^-2`. The time after which two bodies meet will be :A. 2 sB. 4 sC. 6 sD. 8 s |
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Answer» Correct Answer - B Let they meet after time `t`. Then distance traveled by both in time `t` should be same. `s = 8t = (1)/(2) 4t^2 rArr t = 4 s`. |
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