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| 1. |
A boiler is in the form of a cylinder 2 m long with hemispherical ends of 2 m find volume???? |
| Answer» According to the question,we are given that,Diameter of common base = 2 mThen, radius of common base =\xa0{tex}\\frac { 2 } { 2 }{/tex}\xa0= 1 mHeight of the cylinder = 2 mVolume of boiler = Volume of cylinder + 2(Volume of hemisphere){tex}= \\pi r ^ { 2 } h + 2 \\times \\frac { 2 } { 3 } \\pi r ^ { 3 }{/tex}{tex}= \\frac { 22 } { 7 } \\times 1 \\times 1 \\times 2 + 2 \\times \\frac { 2 } { 3 } \\times \\frac { 22 } { 7 } \\times 1 \\times 1 \\times 1{/tex}{tex}= \\frac { 44 } { 7 } + \\frac { 88 } { 21 }{/tex}{tex}= \\frac { 132 + 88 } { 21 }{/tex}{tex}= \\frac { 220 } { 21 } \\mathrm { m } ^ { 3 }{/tex} | |