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| 1. |
A boy observes that the angle of elevation |
| Answer» Let O be the position of the bird and B be the position of the boy. Let FG be the building and G be the position of the girl.In {tex}\\triangle{/tex}OLB,{tex}\\frac { OL } { B O }= \\sin 30 ^ { \\circ }{/tex}{tex}\\Rightarrow \\quad \\frac { O L } { 100 } = \\frac { 1 } { 2 }{/tex}{tex}\\Rightarrow{/tex}\xa0OL = 50 mOM = OL - ML= OL - FG= 50 - 20 = 30 mIn {tex}\\triangle{/tex}OMG{tex}\\frac {OM}{OG}=sin45°=\\frac{1}{√2}{/tex}OG = OM√2 = 30 √2 = 42.3 meter | |