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A boy standing at the top of a tower of `20 m`. Height drops a stone. Assuming `g = 10 ms^-2` towards north. The average acceleration of the body is.A. `20 m//s`B. `40 m//s`C. `5 m//s`D. `10 m//s` |
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Answer» Correct Answer - A We have `v = sqrt(2 gh)` =`sqrt(2 xx 10 xx 20) = sqrt(400) = 20 ms^-1`. |
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