1.

A boy standing at the top of a tower of `20 m`. Height drops a stone. Assuming `g = 10 ms^-2` towards north. The average acceleration of the body is.A. `20 m//s`B. `40 m//s`C. `5 m//s`D. `10 m//s`

Answer» Correct Answer - A
We have `v = sqrt(2 gh)`
=`sqrt(2 xx 10 xx 20) = sqrt(400) = 20 ms^-1`.


Discussion

No Comment Found

Related InterviewSolutions