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A circle touches all four sides of a quadrilateral abcd with ab =6 cm bc=7cm and cd =4cm find ad

Answer» Given,\xa0a circle touches all the four sides of a quadrilateral ABCD whose sides are AB = 6 cm, BC = 9 cm and CD = 8 cm.\xa0If a circle touches all the four sides of quadrilateral ABCD, then\xa0AB + CD = AD + BC{tex}\\therefore{/tex}\xa06 + 8 = AD + 9\xa0{tex}\\Rightarrow{/tex}\xa014 = AD + 9{tex}\\Rightarrow{/tex}\xa014-9 = AD{tex}\\Rightarrow{/tex}\xa0AD = 5 cm


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