1.

A cistern is normally filled by a tap in 5 hours, but suddenly a leak develops and it empties the full cistern in 30 hours with the leak, the cistern is filled in1). 8 hours2). 6 hours3). 10 hours4). 7.5 hours

Answer»

WORK DONE by a tap in one HOUR = 1/5

Work done by leak in one hour = 1/30

Total work done in 1 hour = {(1/5) – (1/30)} = 1/6

∴ Required time = 6 HOURS


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