A compound microscope has lenses of focal length `10 mm and 30 mm`. An object placed at `1.2 cm` from the first lens is seen through the second lens at `0.25 m` from the eye lens. Calculate (i) magnifying power (ii) distance between the two lenses.

A compound microscope has lenses of focal length `10 mm and 30 mm`. An

1.	A compound microscope has lenses of focal length `10 mm and 30 mm`. An object placed at `1.2 cm` from the first lens is seen through the second lens at `0.25 m` from the eye lens. Calculate (i) magnifying power (ii) distance between the two lenses.
Answer» Correct Answer - `-46.7 ; 8.7 cm` Here, `f_(0) = 10 mm = 1 cm, f_(e) = 30 mm = 3 cm` `u_(0) = - 1.2 cm, v_(e) = - 0.25 m = - 25 cm` `M = ? L = ?` From `(1)/(v_(0)) - (1)/(u_(0)) = (1)/(f_(0))` `(1)/(v_(0)) = (1)/(f_(0)) + (1)/(u_(0)) = (1)/(1) - (1)/(1.2) = (0.2)/(1.2) = (1)/(6)` `v_(0) = 6 cm` From `(1)/(v_(e)) - (1)/(u_(e)) = (1)/(f_(e))` `(1)/(u_(e)) - (1)/(v_(e)) - (1)/(f_(e)) = (1)/(-25) - (1)/(3) = (-28)/(75)` `u_(e) = (- 75)/(28) = - 2.7 cm` `M = (v_(0))/(-u_(0))(1 + (d)/(f_(e))) = (6)/(-1.2)(1 + (25)/(3)) = -46.7` `L = v_(0) + \|u_(0)\| = 6 + 2.7 = 8.7 cm`

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A compound microscope has lenses of focal length `10 mm and 30 mm`. An object placed at `1.2 cm` from the first lens is seen through the second lens at `0.25 m` from the eye lens. Calculate (i) magnifying power (ii) distance between the two lenses.

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