1.

√(-a cos alpha-a sin alpha)^2 + (b sin alpha-(-b cos alpha))^2

Answer» Or, a^2 + b^2 + 2SinaCosa( a^2 - b^2)But both are same
(a^2 + b^) 1 - 4sin^2a cos^2aWhere a is alpha


Discussion

No Comment Found