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| 1. |
A cottage industry produces a certain no.of pottery articles |
| Answer» Let cost of production of each article be Rs xWe are given total cost of production on that particular day = Rs 90Therefore, total number of articles produced that day = 90/xAccording to the given conditions,{tex} x = 2 \\left( \\frac { 90 } { x } \\right) + 3{/tex}{tex}\\Rightarrow x = \\frac { 180 } { x } + 3{/tex}{tex}\\Rightarrow x = \\frac { 180 + 3 x } { x }{/tex}{tex}\\Rightarrow x ^ { 2 } = 180 + 3 x{/tex}{tex}\\Rightarrow x ^ { 2 } - 3 x - 180 = 0{/tex}{tex}\\Rightarrow x ^ { 2 } - 15 x + 12 x - 180 = 0{/tex}⇒\xa0x (x − 15) + 12 (x − 15) = 0⇒ (x − 15) (x+ 12) = 0 ⇒\xa0x = 15, −12Cost cannot be in negative, therefore, we discard x = − 12Therefore, x = Rs 15 which is the cost of production of each article.Number of articles produced on that particular day = {tex} \\frac { 90 } { 15 }{/tex}\xa0= 6 | |