1.

A double convex lens made of glass of refractive index `1.56` has both radii of curvature of magnitude `20 cm`. If an object is placed at a distance of `10 cm` from this lens, find the position of image formed.

Answer» Here, `mu = 1.56, R_(1) = 20 cm`,
`R_(2) = -20 cm, u = -10 cm, v = ?`
As `(1)/(f) = (mu -1)((1)/(R_(1)) - (1)/(R_(2)))`
:. `(1)/(f) = (1.56 - 1)((1)/(20) + (1)/(20)) = 0.56 xx (1)/(10)`
`f = (10)/(0.56) = 17.86cm`.
As `(1)/(v) - (1)/(u) = (1)/(f) :. (1)/(v) = (1)/(f) + (1)/(u) = (1)/(17.86) + (1)/(-10)`
`v = -22.72 cm`


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