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A double convex lens made of glass of refractive index `1.56` has both radii of curvature of magnitude `20 cm`. If an object is placed at a distance of `10 cm` from this lens, find the position of image formed. |
Answer» Here, `mu = 1.56, R_(1) = 20 cm`, `R_(2) = -20 cm, u = -10 cm, v = ?` As `(1)/(f) = (mu -1)((1)/(R_(1)) - (1)/(R_(2)))` :. `(1)/(f) = (1.56 - 1)((1)/(20) + (1)/(20)) = 0.56 xx (1)/(10)` `f = (10)/(0.56) = 17.86cm`. As `(1)/(v) - (1)/(u) = (1)/(f) :. (1)/(v) = (1)/(f) + (1)/(u) = (1)/(17.86) + (1)/(-10)` `v = -22.72 cm` |
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