A man goes 15m due west and then 8 m due north . how far the starting

1.	A man goes 15m due west and then 8 m due north . how far the starting point?
Answer» Let the man goes 15m due west from A to B and then 8m due north from B to C then the distance from its starting point is the length of AC By using Pythagoras theorem, in ∆ABC AB² + BC² = AC²=> 15² + 8² = AC²=> 225 + 64 = AC²=> 289 = AC²=> AC = √289 = 17So the man is 17m far from its starting point...... 17 cm

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