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A moving car possesses average velocities of `5 ms^-1, 10 ms^-1 and 15 ms^-1` in the first, second and third seconds respectively. What is the total distance covered by the car in these three seconds ?A. 15 mB. 30 mC. 55 mD. None of these |
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Answer» Correct Answer - B distance covered `= s = v_(av) xx time` For `1st` second : `S_1 = 5 xx 1 = 5 m` For `2nd` second : `S_(2)=10xx1=10 m` For second `3rd` second : `S_1 = 15 xx 1 = 15 m` Total distance traveled `S = S_1 + S_2 + S_3 = 5 + 10 + 15 = 30 cm`. |
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