1.

A pipe is open at both ends. What should be its length such that it resonates a 10Hz source in the 2nd harmonic? Speed of sound in air = 340m/s.(a) 34m(b) 68m(c) 17m(d) 51mThe question was posed to me during an interview.My query is from Reflection of Waves topic in portion Waves of Physics – Class 11

Answer»

Right answer is (a) 34m

The best I can EXPLAIN: For a PIPE open at both ENDS frequency ‘f’ = nv/2L, where n is speed of sound.

Given: f = 10 & n=2.

∴ 10 = 2*340/2L

∴ L = 680/20

= 34m.



Discussion

No Comment Found

Related InterviewSolutions