A plane mirror is placed at the bottom of a tank containing a liquid o

1.	A plane mirror is placed at the bottom of a tank containing a liquid of refractive index μ. P is a small object at a height h above the mirror. An observer O—vertically above P, outside the liquid—sees P and its image in the mirror. The apparent distance between these two will be(a) 2μh (b) 2h/μ(c) 2h/μ - 1(d) h(1 + 1/μ)
Answer» Correct Answer is: (b) 2h/μ The image of P will be formed at a distance h below the mirror. If d = depth of the liquid in the tank, apparent depth of P = x₁ = d-h/μ, apparent depth of the image of P = x₂ = d+h/μ, apparent distance between P and its image = x₂ - x₁ = 2h/μ.

A plane mirror is placed at the bottom of a tank containing a liquid of refractive index μ. P is a small object at a height h above the mirror. An observer O—vertically above P, outside the liquid—sees P and its image in the mirror. The apparent distance between these two will be(a) 2μh (b) 2h/μ(c) 2h/μ - 1(d) h(1 + 1/μ)

Answer»

Correct Answer is: (b) 2h/μ

The image of P will be formed at a distance h below the mirror. If d = depth of the liquid in the tank,

apparent depth of P = x₁ = d-h/μ,

apparent depth of the image of P = x₂ = d+h/μ,

apparent distance between P and its image = x₂ - x₁ = 2h/μ.

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