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A pole stands vertically on the floor. From a point, it is 120 meters away from the foot of the pole and the angle of elevation is 45° then find the height of the pole.(a) 100 meters(b) 180 meters(c) 120 meters(d) 10 metersI got this question in final exam.Asked question is from Trigonometry Application topic in division Trigonometry Application of Mathematics – Class 10

Answer»

Right OPTION is (c) 120 meters

To explain: In the figure, BC is the HEIGHT of the pole.

In ∆ABC, TAN 45° = \(\FRAC {BC}{AB}\)

1 = \(\frac {BC}{AB}\)

1 = \(\frac {BC}{120}\)

BC = 120 meters


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