A quadrilateral ABCD is drawn to circumscribe a circle. Prove that : A

1.	A quadrilateral ABCD is drawn to circumscribe a circle. Prove that : AB +CD = AD+BC
Answer» We know that the tangent segments from an external point to a circle are equal\xa0{tex}\\therefore{/tex} AP = AS ........(1)BP = BQ .......(2)CR = CQ .......(3)DR = DS .......(4)Adding (1), (2), (3) and (4), we get(AP + BP) + (CR + DR) = (AS + BQ + CQ + DS){tex}\\Rightarrow{/tex}\xa0AB + CD = (AS + DS) + (BQ + CQ){tex}\\Rightarrow{/tex}\xa0AB + CD = AD + BC Tq my dear frnd..... It helps me a lot..... ✌️?

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