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A radioactive particle at rest, having mass 10g, breaks into 2 fragments (1&2) in the mass ratio 2:3 respectively. If the first one moves with a velocity of 10m/s what will be the speed of the second particle?(a) 4.33 m/s(b) -4.33 m/s(c) -6.67 m/s(d) 6.67 m/sThe question was asked in an online interview.Enquiry is from Linear Momentum of a System of Particles topic in portion System of Particles and Rotational Motion of Physics – Class 11

Answer»

Correct option is (C) -6.67 m/s

Explanation: let the mass of part 1 be 2X, & the mass of part 2 be 3x SINCE the masses are in the ratio 2:3.2x + 3x = 10g.

∴ x = 2g. Therefore, masses of part 1 & 2 are 4g & 6g respectively.

The total momentum will be CONSERVED because there is no EXTERNAL force.Let the velocity of 2nd part be ‘v’.

∴ 0 = 4*10 + 6*v∴ v = -40/6 = -6.67 m/s.



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