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A rectangle having sides x+3y,7,13,3x+y.Find the value of x and y. |
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Answer» We know Opposite sides of a rectangle are equal So, x+3y=13.......(1)3x+y=7.............(2)By elimination method Equation (1) multiply by 3 So , 3x+9y=39 3x+ y=7 (on subtraction)We give, y=4 Now ,put the value of y in equation (1) X+3y =13 X+3(4)= 13 X=13-12 X=1 Y=1 and x=4 |
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