1.

A rectangle is inscribed in a semi-circle of radius `r`with one of its sides on diameter of semi-circle. Find the dimensionsof the rectangle so that its area is maximum. Find also the area.

Answer» `b=sqrt(r^2-(a/2)^2`
`b=sqrt(4r^2-a^2)/2`
Area of A=`a*b=a*(sqrt(4r^2-a^2)/2)`
diff with respect to a
`(dA)/(da)=sqrt(4r^2-a^2)/2`
`=a/2*1/2*1/sqrt(4r^2-a^2)*-2a`
`(dA)/(da)=sqrt(4r^2-a^2)/2-a^2/(2sqrt(4r^2-a^2))=0`
`(4r^2-a^2-a^2)/(2sqrt(4r^2-a^2))=0`
`4r^2=2a^2`
`a=pmsqrt2r`
`b=sqrt(4r^2-a^2)/2=sqrt2r/2=4/sqrt2`
Area=`r^2.`


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