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Determine the points on the curve `x^2=4y`which are nearest to the point (0,5). |
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Answer» `d=sqrt((x_1-o)^2+(y_1-5)^2)` `d=sqrt(4y_1+(y_1-5)^2` `d/(dy_1)=1/(2sqrt(4y_1+(y_1-5)^2))*(4+2(y_1-5))=0` `4+(2(y_1-5)=0` `y_1=3` `x_1^2=4y_1` `x_1=pm2sqrt3` Points=`(2sqrt3,3),(-2sqrt3,3).` |
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