1.

The strength of a beam varies as the product of its breadth and squareof its depth. Find the dimensions of the strongest beam which can be cut from a circular log of radius `adot`

Answer» `b^2/4+d^2/4=a^2`
`d^2=4a^2-b^2`
`(dS)/(db)=b(-2b)+(4a^2-b^2)`
`=-2b^2+4a^2-b^2`
`=4a^2-3b^2=0`
`b^2=4/3a^2`
`b=pm2/sqrt3`
`d^2=4a^2-b^2`
`=4a^2-4/3a^2`
`d=2sqrt(2/3)a`
`(d^2S)/(db^2)=-4b-2b`
`=-6b<0`
this will be maximum.


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