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The total cost of producing `x`radio sets per day is `R sdot((x^2)/4 35 x+25)`and the price per set at which they may be sold is `R sdot(50-x/2)dot`Find the daily output to maximize the total profit. |
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Answer» Here, total cost of `x` radios ` = x^2/4+35x+25` Rs Selling price of `x` radios ` = x(50-x/2) = 50x-x^2/2` Rs `:.` Profit `(P)= 50x-x^2/2 - (x^2/4+35x+25)` Rs `=> P = -3/4x^2 + 15x -25` `=>(dP)/dx = -3/2x + 15` For, maximum profit, `(dP)/dx` should be `0`. `=> -3/2x + 15 = 0` `=> x = 10` So, to maximize the total profit, `x` should be `10`. |
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