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| 1. |
A sector of a circle of radius 10.5cm then find the perimeter of sector where angle is 60 |
| Answer» r = 10.5 cm , θ = 60oPerimeter of the sector = 2r +\xa0{tex}\\frac { 2 \\pi r \\theta } { 360 ^ { \\circ } }{/tex}{tex}= 10.5 \\times 2 + 2 \\times \\frac { 22 } { 7 } \\times \\frac { 10.5 \\times 60 } { 360 }{/tex}{tex}= 21 + 2 \\times22 \\times1.5 \\times \\frac { 1 } { 6 }{/tex}{tex}= 21 + 22 \\times1.5 \\times \\frac { 1 } { 3}{/tex}{tex}= 21 + 11 = 32{/tex} cm | |