A sinusoidal wave has an amplitude of 2cm. It is travelling in the negative x-direction. The distance between two crests is 2cm. The angular frequency is πs^-1. What is the displacement of the particle at x = 20.5cm, at t = 10s? Assume that at t=0 & x=0 the particle was at the mean position and going downwards. ‘x’ &’y’ are in cm.(a) 0cm(b) 1cm(c) -1cm(d) -2cmThe question was posed to me in quiz.The doubt is from Displacement Relation in a Progressive Wave topic in section Waves of Physics – Class 11

A sinusoidal wave has an amplitude of 2cm. It is travelling in the neg

1.	A sinusoidal wave has an amplitude of 2cm. It is travelling in the negative x-direction. The distance between two crests is 2cm. The angular frequency is πs^-1. What is the displacement of the particle at x = 20.5cm, at t = 10s? Assume that at t=0 & x=0 the particle was at the mean position and going downwards. ‘x’ &’y’ are in cm.(a) 0cm(b) 1cm(c) -1cm(d) -2cmThe question was posed to me in quiz.The doubt is from Displacement Relation in a Progressive Wave topic in section Waves of Physics – Class 11
Answer» Right CHOICE is (d) -2CM Easy explanation: The equation suiting the given CONDITIONS will be: y = ASIN(kx+wt+a) At x=0, t=0, velocity is negative, so ‘a’ will be π. k = 2π/λ = π. ∴ y = 2sin(πx + 2T + π). At x=20cm & t=10s, y = 2sin(20.5π + 10π + π) = 2sin(31.5π) = -2cm.

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