1.

A small object is kept symmetrically between two plane mirrors inclined at 38°. This angle is now gradually increased to 41°, the object being symmetrical all the time. Determine the number of images visible during the process.

Answer»

The object is kept symmetrically between two plane mirrors. This implies the object is placed at angle bisector.

Thus, for θ = 38°,

n = \(\frac{360}{38}\) = 9.47

As it is not integral, N = 9 (the integral part of n)

∴ For going from 38° to 41°, the mirrors go through angles 39° and 40°.

Number of images formed will remain 9 for all angles between 38° and 40°.

For angles > 40°, the n goes on decreasing and when θ = 41°,

n = \(\frac{360}{41}\) = 8.78 i.e., N = 8



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