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A small object is kept symmetrically between two plane mirrors inclined at 38°. This angle is now gradually increased to 41°, the object being symmetrical all the time. Determine the number of images visible during the process. |
Answer» The object is kept symmetrically between two plane mirrors. This implies the object is placed at angle bisector. Thus, for θ = 38°, n = \(\frac{360}{38}\) = 9.47 As it is not integral, N = 9 (the integral part of n) ∴ For going from 38° to 41°, the mirrors go through angles 39° and 40°. Number of images formed will remain 9 for all angles between 38° and 40°. For angles > 40°, the n goes on decreasing and when θ = 41°, n = \(\frac{360}{41}\) = 8.78 i.e., N = 8 |
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