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A small spherical ball of diameter 5mm is thrown into a well of water and it moves with a terminal velocity 10cm/s. Calculate the density of the spherical ball. Given that viscosity of water is 0.01poise.(a) 1.0083 gm/cm^3(b) 1.0000 gm/cm^3(c) 1.0023 gm/cm^3(d) 1.0073 gm/cm^3I had been asked this question in class test.I'm obligated to ask this question of Viscosity Measurement in section Fluid Flow and Mixing of Bioprocess Engineering

Answer» CORRECT answer is (d) 1.0073 gm/cm^3

The BEST explanation: According to Stoke’s THEOREM,

\(v_t = \frac{2}{9} \frac{r^2}{\eta} (\sigma – \rho) g\)

Here,

\((\sigma – 1) = \frac{10×9×0.01}{2×(0.25)^2×981}\) = 0.0073

= 1.0073 gm/cm^3


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