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A small spherical ball of diameter 5mm is thrown into a well of water and it moves with a terminal velocity 10cm/s. Calculate the density of the spherical ball. Given that viscosity of water is 0.01poise.(a) 1.0083 gm/cm^3(b) 1.0000 gm/cm^3(c) 1.0023 gm/cm^3(d) 1.0073 gm/cm^3I had been asked this question in class test.I'm obligated to ask this question of Viscosity Measurement in section Fluid Flow and Mixing of Bioprocess Engineering |
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Answer» CORRECT answer is (d) 1.0073 gm/cm^3 The BEST explanation: According to Stoke’s THEOREM, \(v_t = \frac{2}{9} \frac{r^2}{\eta} (\sigma – \rho) g\) Here, \((\sigma – 1) = \frac{10×9×0.01}{2×(0.25)^2×981}\) = 0.0073 = 1.0073 gm/cm^3 |
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