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A solution of the equation cos2 x + sin x + 1 = 0, lies in the interval A. (- \(\frac{π}4\), \(\frac{π}4\)) B. (\(\frac{π}4\), \(\frac{3π}4\)) C. (\(\frac{3π}4\), \(\frac{5π}4\)) D. (\(\frac{5π}4\), \(\frac{7π}4\)) |
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Answer» 1 - sin2x + sin x +1 = 0 sin2x - sin x - 2 = 0 sin x = - 1 x = \(\frac{3π}2\) Option D |
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