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If cos x + √3 sin x = 2, then x = A. \(\frac{π}3\)B. \(\frac{2π}3\)C. \(\frac{4π}3\)D.\(\frac{5π}3\) |
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Answer» cos2x = (2 - √3 sin x)2 1-sin2x = 4+3 sin2x - 4√3 sin x 4 sin 2x - 4√3 sin x+3 = 0 sin x = \(\frac{\sqrt3}2\) x = \(\frac{π}3\) Option A |
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