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If cos x = k has exactly one solution in [0, 2 π], then write the value(s) of k. |
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Answer» As cos x = cos θ Then x = 2nπ ± θ And it is said that it has exactly one solution. So θ = 0 and x = \(\frac{2nπ}2\) =nπ In the given interval taking n = 1,x = π {n = 0 is not possible as cos 0 = 1 not -1 but cos π is -1} |
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