1.

If cos x = k has exactly one solution in [0, 2 π], then write the value(s) of k.

Answer»

As cos x = cos θ 

Then x = 2nπ ± θ 

And it is said that it has exactly one solution. 

So θ = 0 and 

x = \(\frac{2nπ}2\)

=nπ 

In the given interval taking n = 1,x = π {n = 0 is not possible as cos 0 = 1 not -1 but cos π is -1}



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