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A stationary swimmer `S`, inside a liquid of refractive index `mu_(1)`, is at a distance `d` from a fixed point `P` inside the liquid. A rectangular block of width `t` and refractive index `mu_(2)(mu_(2) lt mu_(1))` is now placed between `S` and `P.S` will observer `P` to be at a distanceA. `d-t((mu_(1))/(mu_(2))-1)`B. `d-t(1-(mu_(2))/(mu_(1)))`C. `d+t(1-(mu_(2))/(mu_(1)))`D. `d+t((mu_(1))/(mu_(2))-1)` |
Answer» Correct Answer - D |
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