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A tank is filled with water to a height of `12.5 cm` The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be `9.4cm`. What is the refractive index of water ? If water is replaced by a liquid of refractive index `1.63` upto the same height, by what distance would the microscope have to be moved to focus on the needle again ? |
Answer» Here, real depth `= 12.5 cm` , apparent depth `= 9.4 cm , mu = ?` As `mu = ("real depth")/("apparent depth") :. mu = (12.5)/(9.4) = 1.33` Now, in the second case, `mu = 1.63`, real depth `= 12.5 cm` , apparent depth, `y = ?` `:. 1.63 = (12.5)/(y)` `y = (12.5)/(1.63) = 7.67 cm` `:.` Distance through which microscope has to be moved up `= 9.4 - 7.67 = 1.73 cm` |
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