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| 1. |
A toy is in the form |
| Answer» \xa0Radius of the cone = 3.5 cm{tex}\\therefore {/tex}\xa0Radius of the hemisphere = 3.5 cmTotal height of the toy = 15.5 cm{tex}\\therefore {/tex}\xa0Height of the cone = 15.5 - 3.5 = 12 cmSlant height of the cone = {tex}\\sqrt {{{(3.5)}^2} + {{(12)}^2}} = \\sqrt {12.25 + 144} {/tex}{tex} = \\sqrt {156.25} {/tex}\xa0= 12.5 cm{tex}\\therefore {/tex}\xa0Total surface area\xa0of the toy = Curved surface area\xa0of hemisphere + Curved surface area\xa0of cone{tex} = 2\\pi {r^2} + \\pi rl = 2\\pi {(3.5)^2} + \\pi (3.5)(12.5){/tex}{tex} = 24.5\\pi + 43.75\\pi = 68.25\\pi = 68.25 \\times \\frac{{22}}{7}{/tex}\xa0= 214.5 cm2 | |