A train starts full of passengers at the first station it drops 1/3 of

1.	A train starts full of passengers at the first station it drops 1/3 of the passengers and takes 280 more at the second station it drops one half the new total and takes twelve more on arriving at the third station it is found to have 248 passengers. Find the no of passengers in the beginning?
Answer» Let no of passengers in the beginning be x After first station no passengers=(x-x/3)+280=2x/3 +280 After second station no passengers =1/2(2x/3+280)+12 1/2(2x/3+280)+12=248 2x/3+280=2*236 2x/3=192 x=288

A train starts full of passengers at the first station it drops 1/3 of the passengers and takes 280 more at the second station it drops one half the new total and takes twelve more on arriving at the third station it is found to have 248 passengers. Find the no of passengers in the beginning?

Answer»

Let no of passengers in the beginning be x

After first station no passengers=(x-x/3)+280=2x/3 +280

After second station no passengers =1/2(2x/3+280)+12

1/2(2x/3+280)+12=248

2x/3+280=2*236

2x/3=192

x=288