a2x2+3abx+2b2Find the roots

1.	a2x2+3abx+2b2Find the roots
Answer» a²x² - 3abx + 2b² = 0a²x² - 3abx = - 2b²divide each term with a² both sides of theequation ,x² - 3bx/a = - 2b²/a²x² - 2 × x × (3b/2a)+(3b/2a)² = ( 3b/2a )² - 2b²/a²( x - 3b/2a )² = 9b²/4a² - 2b² /a²= ( 9b² - 4b² ) /a²= 5b²/a²x - 3b/2a = ± √ ( 5b²/a² )x = 3b/2a ± √5 ( b/a )= [ 3b ± 2√5 b ] / 2a= ( 3 ± 2√5 )b/ 2a(I hope this helps you.)???

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