Saved Bookmarks
| 1. |
∆ABC~∆DEF, If DE = 2AB and BC= 3cm then EF is equal to |
| Answer» Given that\xa0{tex}\\triangle{/tex}ABC ~ {tex}\\triangle{/tex}DEFWe know that when two triangles are similar, then the ratios of the lengths of their corresponding sides are equal.\xa0{tex}\\Rightarrow \\frac { A B } { D E } = \\frac { B C } { E F }{/tex}{tex}\\Rightarrow \\frac { 1 } { 2 } = \\frac { 3 } { E F }{/tex}{tex}\\Rightarrow{/tex}\xa0EF = {tex}\\frac 32{/tex} cm | |