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ABC is s triangle right angled at C.If angle A=30°\'AB=12cm,determine BC and AC |
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Answer» sin 30 = BC/ABBC = AB X Sin\xa030 = 12 X 1/2 = 6 cmcos 30 = AC / AB AC = AB X COS 30 = 12 X {tex} \\sqrt{3}/2{/tex} = 6\xa0{tex} \\sqrt{3}{/tex} cm sin30°= BC/12BC=1/2×12 =6cm.6/AC=1/√3AC=6√3 cm |
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