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| 1. |
abx2+(b2-ac)x-bc=0 yeh jo 2 hai vo x ka square hai..or b mai bhi.. |
| Answer» {tex}abx^2 + (b^2 - ac)x - bc = 0\xa0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}abx^2 + b^2x - c(ax + b) = 0\xa0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}bx(ax + b) - c(ax + b) = 0\xa0{/tex}{tex}\\Rightarrow{/tex}{tex}(bx - c)(ax + b) = 0\xa0{/tex}x =\xa0{tex}\\frac{c} {b}{/tex},\xa0{tex}\\frac{-b}{a}{/tex} | |