According to Bohr's theory, the radius of electron in an orbit describ

1.	According to Bohr's theory, the radius of electron in an orbit described by principal quantum number n and atomic number Z is proportional to:1. Z2n22. Z2 / n23. Z2 / n4. n2 / Z
Answer» Correct Answer - Option 4 : n2 / Z Concept: Bohr’s theory: He proposed that the electrons orbited in a specific orbit with a fixed radius of shells, with a fixed radius. According to Bohr's model, the electron would absorb energy in the form of photons to get excited to a higher energy level. It derives a radius for the nth excited state of hydrogen-like atoms. The radius of Bohr's orbit \(Z = \frac{{{n^2}{h^2}}}{{4{\pi ^2}m{e^2}}} \times \frac{1}{Z}\) Where n = principal quantum number of orbit, Z = atomic number, h = Plank’s constant, m = Mass of electron, e = elementary charge Explanation: From the above discussion, it is clear that the r is directly proportional to n2. From Bohr’s relation, r ∝ n2 So the correct option isn2/ Z.

According to Bohr's theory, the radius of electron in an orbit described by principal quantum number n and atomic number Z is proportional to:1. Z2n22. Z2 / n23. Z2 / n4. n2 / Z

Answer» Correct Answer - Option 4 : n2 / Z

Concept:

Bohr’s theory: He proposed that the electrons orbited in a specific orbit with a fixed radius of shells, with a fixed radius.
- According to Bohr's model, the electron would absorb energy in the form of photons to get excited to a higher energy level.
- It derives a radius for the nth excited state of hydrogen-like atoms.

The radius of Bohr's orbit

\(Z = \frac{{{n^2}{h^2}}}{{4{\pi ^2}m{e^2}}} \times \frac{1}{Z}\)

Where n = principal quantum number of orbit, Z = atomic number, h = Plank’s constant, m = Mass of electron, e = elementary charge

Explanation:

From the above discussion, it is clear that the r is directly proportional to n2.