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All the identities of a&bPlease |
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Answer» Thanks (a + b)2 = a2 + 2ab + b2(a – b)2 = a2 – 2ab + b2 a2 – b2 = (a + b)(a – b)(x + a)(x + b) = x2 + (a + b) x + ab(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca(a + b)3 = a3 + b3 + 3ab (a + b)(a – b)3 = a3 – b3 – 3ab (a – b)a3 + b3 + c3– 3abc = (a + b + c)(a2 + b2 + c2 – ab – bc – ca) Here is your answer hope it helps!!? |
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