InterviewSolution
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InterviewSolution
| 1. |
AM is a median of a triangle ABC is AB+BC>2AM? |
| Answer» In {tex}\\triangle{/tex}ABMAB + BM > AM....[Sum of the lengths of any two sides of a triangle is greater than the length of the third side].....(1)In {tex}\\triangle{/tex}ACMCA + CM > AM....[Sum of the lenghts of any two sides of a triangle is greater than the length of the third side].....(2)Sum (1) and (2)(AB + BM) + (CA + CM) > AM + AM{tex}\\therefore{/tex}\xa0AB + (BM + CM) + CA > 2AM{tex}\\therefore{/tex}\xa0AB + BC + CA > 2AM | |