1.

An AP co sists of 50 terms of which 3rd term is 12 and the last term is 106.Find the 29th term.

Answer» A3= 12 with the help of this a+ 2d = 12 equation 1.Ap = 50 a50 = 106 again with the help of this a+ 49d =106 equation 2 And solve these equation y get the ans
n = 50a3 = 12 -> a + 2d = 12 ->a = 12 - 2dl = 106an =a + (n-1) d106 = a + (50-1)d106 = 12 - 2d+ 49d106-12=47d94=47dd=94÷47=2d=2a=12-2(2)a=12-4a=8a29= a+28da29=8+28(2)a29=8+56a29=64Your answer is 64


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