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An ap consists of 50 terms of which 3rd term is 12 and the last term is 106 find the 29th term

Answer» a3 = 12 expand ita + 2d = 12n = 50a50 = a + 49d = 106Eliminate the equation u will get the value of d as 2 and a = 8Now, a29 = a + 28d = 8 + 28× 2 =8+56 = 64


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