Saved Bookmarks
| 1. |
An AP consists of 50 terms of which 3rd term is 12 &the last term is 106. Find the 29th term |
|
Answer» a 3= 12a n= 106 and n=50a 3= a+2d=12......eqa.1a n = a+(n-1)d= 106a+(50-1)d=106a+49d=106......eqa.2Subtracting eqa.1 from 2 47d = 106 - 12= 94d = 94/47=2putting the value of d in eqa.1a + 2×2 = 12a = 12 - 4 =8a 29 = a + (29 - 1)d= 8 + 28 × 28 + 56 = 64 answer........ 64 |
|