An AP consists of 50 terms of which 3rd term is 12 and last term is 106.find the 29th term

An AP consists of 50 terms of which 3rd term is 12 and last term is 10

1.	An AP consists of 50 terms of which 3rd term is 12 and last term is 106.find the 29th term
Answer» Let a , d are first term and commondifference of an A.Pnth term = Last term = a + ( n - 1 )dan = a + ( n - 1 )dNow ,It is given that ,Third term = 12a + 2d = 12 ------( 1 )Last term = 106a + 49d = 106 ---( 2 )Subtract ( 1 ) from ( 2 ) , we get47d = 94d = 2Substitute d value in equation ( 1 ) ,We geta + 2 × 2 = 12a = 12 - 4a = 829th term = a + 28da29 = 8 + 28 × 2= 8 + 56= 64