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An astronomical telescope has an angular magnification of magnitude 5 for distant object. The separation between the objective and the eyepiece is 36 cm and the final image is formed at infinity. The focal length `f_(0)` of the objective and the focal length `f_(0)` of the eyepiece areA. `f_(0) = 45 cm and f_(e) = - 9 cm`B. `f_(0) = 50 cm and f_(e) = 10 cm`C. `f_(0) = 7.2 cm and f_(e) = 5 cm`D. `f_(0) = 30 cm and f_(e) = 6 cm` |
Answer» Correct Answer - D Here, Angular magnification of telescope `= (f_(0))/(f_(e)) = 5`, `:. f_(0) = 5 f_(e)` …(i) Now, `f_(0) + f_(e) = 36 cm` …(ii) On solving (i) and (ii), we get `5 f_(e) + f_(e) = 36 cm` `f_(e) = 6 cm, f_(0) = 30 cm` |
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