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An equation of a wave is given by: y = 2sin(3x-2t+π/2). What is the minimum distance between two points having the same phase?(a) 3(b) π/2(c) 2π/3(d) πThe question was asked in examination.Origin of the question is Displacement Relation in a Progressive Wave in chapter Waves of Physics – Class 11

Answer»

The CORRECT answer is (c) 2π/3

Best explanation: In the GIVEN equation the phase is 3x-2t+π/2.

This is repeated after every 2π.

∴ sin( 3x-2t+π/2) +2nπ = sin( 3x-2t+π/2).We can consider the case at t=0, sin(3x+π/2) = sin(3x+π/2+2nπ)OR cos(3x) = cos(3x+2nπ)∴ n = 1 for MINIMUM difference.Minimum distance can be FOUND from KX = 2πOR x = 2π/k = 2π/3.



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