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An object is placed at a distance of 30 cm from a concave lens of focal length 15 cm. An erect and virtual image is formed at a distance of 10 cm from the lens. Calculate the magnification. |
Answer» Type of lens is Cancave lens. Formula: Magnification m = \(\frac{u}{v}\) Object distance u = -30 cm Image distance v = -10 cm m = \(\frac{-10}{-30}\) = \(\frac{1}{3}\) = +0.33 |
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