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An object of length 2.5 cm is placed at the principal axis of a concave mirror at a distance 1.5f. The image height is(a) + 5 m (b) -5 cm (c) – 10 cm (d) + 1 cm |
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Answer» (b) -5 cm m = \(\frac{f}{f-u} = \frac{f}{f-1.5f}\) = -2cm Height image = m x height of object -2 x 2.5 = – 5 cm |
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